Re is the ratio of vac and iac, see equation 18.1. Assuming the rectifier works without loss, Re is also the ratio of vg and ig. In 18.10, it is stated that we can assume that an undistorted ac line current wave is produced. This can only be true if the rectifier is ideal. I have therefore assumed that the losses occur in the boost converter only, not in the rectifier. Then Re is easy to calculate. Anybody else use the same approach?
Hi,
ReplyDeleteRe is the ratio of vac and iac, see equation 18.1. Assuming the rectifier works without loss, Re is also the ratio of vg and ig. In 18.10, it is stated that we can assume that an undistorted ac line current wave is produced. This can only be true if the rectifier is ideal. I have therefore assumed that the losses occur in the boost converter only, not in the rectifier. Then Re is easy to calculate. Anybody else use the same approach?
Regards,
Toby