Thursday, March 31, 2011

Lecture 28 Slide 9

My question is regarding the CPM Buck converter example on slide 9 of lecture 28. If Ma = M2 = M1 = 1A/us, how do we arrive at .11/A for Fm?

4 comments:

  1. Fm is not 0.11
    Fm=0.1
    Units of Fm are: (1/A) or A^(-1).

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  2. So it is a typo. Thanks for the response Vojkan.

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  3. It’s not a typo.
    Fm=0.1 and the units are 1/A, when these two are merged together: number one from the expression Fm=0.1 and number one from the units are next to each other and form Fm=0.11/A

    Maybe it would less confusing if:
    - the units are separated from the number in the parentheses Fm=0.1 (1/A) or
    - the units are written as A^(-1):
    Fm=0.1 A^(-1)

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  4. OK. I get it now. That is a confusing way to write it. It would be less confusing as 0.1A^-1. Thanks for the explanation.

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