Wednesday, January 30, 2013

HW2 Prob 2A Stuck on Algebra

Hello:

I am having major trouble with the algebra for problem 2A.  There must be something that I am missing.

The voltage equation is fine and okay to put into the model.  However, when solving for i2, I cannot isolate (d'/d)*<i1> and when solving for i1, I cannot isolate (d/d')*<i2>.  Therefore I cannot solve the transformer.

The approach I am taking is to solve for Ion and then plug into the other current equation.  This leaves the currents multiplied by a factor of 1/(d+(tr/Ts)).  I can combine all of the terms by taking the common denominator, but this leaves a very messy numerator term which does not help much.

Also, if I add the two current equations, I can eliminate a lot of variables.  This results in <i1>+<i2> = Ion which is not much help.

Any assistance will be much appreciated!  Just some small hint will probably help me get to the next step so that I can proceed with the assignment.

If anyone is having similar problems, let's put our heads together to solve this.  I can email you what I have so far and then we can go from there.  I also am available for email, gchat, fb, or cell phone.

Thank you,
Alex

10 comments:

  1. hi alex. you can mail me what you have at vincent.din@colorado.edu

    i'm workin through this, too. i can email you once i figure something out.

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  2. i used

    = Ion(d+tr/Ts) + Qr/Ts

    before plugging this into my expression, i distributed the Ion term. i did not end up with any d+tr/Ts factors.

    hope this helps

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    Replies
    1. sorry that is an expression for i1, average value

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    2. i ended up with an Ion factor in my i2 expression. reworking it now...

      Delete
  3. After eliminating Ion, I get the following equation:
    (d'-tr/Ts) = (d+tr/Ts) + Qr/Ts
    The equation seems consistent. You can see that the tr/Ts terms simply shift the duty cycle and hence the transformer ratio a bit. If this equation is fine, is there a way to contruct the equivalent circuit with dependent current sources on both sides, similar to page 20 in the lecture 4 notes? In other words, can we build it with a dependent source on the primary and a dependent source in the secondary? Would it model the equation correctly? Any thoughts would be greatly appreciated.

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  4. Hi Drew,

    I reworked the algebra. Not sure if your formatting got messed up, but this is the equation I got (looks the same):

    i1_avg = i2_avg * (d+tr/Ts)/(d'-tr/Ts) + Qr/Ts

    It would appear that constructing the circuit with additional dependent sources would make sense, though the professor answered another blog post in a way that suggested we should not have dependent sources, so I am unsure.

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  6. Hi Alex,
    I used the fact that (1-d)>tr/Ts and found avg.ion to be (+Qr/Ts)/d'. I used this to solve for avg.i1. i ended up with avg.i1 =(d/d'+tr/Tsd')+Qr/Tsd'. This made it easy to build the model with d':d transformer.

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    Replies
    1. Hi praSANTA:

      Thank you for the idea. I solved the circuit differently though. I solved both current equations for Ion and then set the two Ion values equal to each other.

      I think this does the job.

      My only concern is that I have two dependent current sources in the circuit (similar to fig 7.56). Since the example shown in fig 7.56 has these type of current sources, I am leaving my circuit this way.

      Thanks everyone for the input.

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