Blog for students taking ECEN5807 Modeling and Control of Power Electronics, ECEE Department, University of Colorado at Boulder, Spring 2013
Thursday, April 28, 2011
18.14 Vcontrol
I'm not sure how to go about finding Vcontrol. Using equation 18.50, and assuming we are in equilibrium so Pav=Pload, I get Vcontrol=500V. This is obviously wrong. So I'm missing something here. Any hints?
There is a typo fig. 18.47. Peak detector output,z, is VM/100 (not VM). Also, Vref1 = kv*x*y/z^2. Vref1=va under steady state. You know the relation between va and ig. Proceed from here.
Both with equation 18.50 and with the method Nitish prescribed, I arrive at Vcontrol=500V.
There is yet another way to approach this. In steady state Vref2-V/100=3.85-385/100=0V. That would suggest Vcontrol=0V, as Vcontrol=Gcv*(Vref2-V/100). I believe this answer is wrong, as it Vcontrol=0V means trouble in 18.14e. However, I don't know how to explain this.
There is a typo fig. 18.47. Peak detector output,z, is VM/100 (not VM). Also, Vref1 = kv*x*y/z^2. Vref1=va under steady state. You know the relation between va and ig. Proceed from here.
ReplyDeleteBoth with equation 18.50 and with the method Nitish prescribed, I arrive at Vcontrol=500V.
ReplyDeleteThere is yet another way to approach this. In steady state Vref2-V/100=3.85-385/100=0V. That would suggest Vcontrol=0V, as Vcontrol=Gcv*(Vref2-V/100). I believe this answer is wrong, as it Vcontrol=0V means trouble in 18.14e. However, I don't know how to explain this.
Anyone have any thoughts on this?
We need to take into account that vg is scaled by 100. We can then use equation 18.50 to find the correct Vcontrol.
ReplyDelete