Wednesday, February 20, 2013

HW5 Sepic

Hello:

On the analysis for the zeros of the Sepic, it shows the step where the d^ voltage source divided by the d^ current source reduces down to -(D'/D)^2*R.  Why is the d^ voltage source treated as negative and thus the equivalent resistance is negative.

Thanks
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2 comments:

  1. KeithFebruary 20, 2013 at 10:58 AM

    Alex,
    This comes from vtest/itest. If you draw the circuit loop that includes the vtest source, dhat voltage source, and dhat current source you will find that vtest = -V1*dhat/D/D'.
    - KT

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    Replies
    1. UnknownFebruary 21, 2013 at 4:45 AM

      KT

      Thanks for your insight. This helped me greatly!

      Alex

      Delete

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